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Kent can paint a certain house by himself in x days. His helper Keith can paint the same house by himself in x 3 days. Suppose we work together at work for 2 days. To complement the use of the fact that the work is the product of velocity and time. What I discovered was – Ok, I do not remember the theories behind the formula, but this is what happened. . (X + (x 3) / 2) – 2 * 2 = number of days remaining where (x + (x 3) / 2) is the rate that you can paint more or less just the average speed between the two, and 2 * 2 reflects the amount of time spent times the number of individuals who paints, so for example, if x = 5, then: (5 + (5 + 3) / 2) – 2 * 2 (5 +8 ) / 2.4 13/2 – 4 6. 5-4 = 2. 5 days left to paint I'm not sure if this is what you are looking for, but it makes sense to me. Of course, you could use the traditional formula: Speed = Count / Time given the amount and time, you can solve for Change. Or, if you are given speed and time can be solved by the quantity: Quantity = rate x time or given rate and amount, can be solved for Time, Time = Amount / Rate but in reality they have only given the time, and never clearly stated what the formula should be resolved.

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Updated: April 3, 2014 — 7:01 am
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