Kent can paint a certain house by himself in x days. His helper Keith can paint the same house by himself in x 3 days. Suppose we work together at work for 2 days. To complement the use of the fact that the work is the product of velocity and time. And so today I learned that … Well, I do not remember the theories behind the formula, but this is what happened. . (X + (x 3) / 2) – 2 * 2 = number of days remaining where (x + (x 3) / 2) is the rate that you can paint more or less just the average speed between the two, and 2 * 2 reflects the amount of time spent times the number of individuals who paints, so for example, if x = 5, then: (5 + (5 + 3) / 2) – 2 * 2 (5 +8 ) / 2.4 13/2 – 4 6. 5-4 = 2. 5 days left to paint I'm not sure if this is what you are looking for, but it makes sense to me. Of course, you could use the traditional formula: Speed = Count / Time given the amount and time, you can solve for Change. Or, if you are given speed and time can be solved by the quantity: Quantity = rate x time or given rate and amount, can be solved for Time, Time = Amount / Rate but in reality they have only given the time, and never clearly stated what the formula should be resolved.
John Burbidge, author of "watching paint dry" shows how to spray paint the exterior of your home and get professional results. Visit